Can someone help me with my geometry work

Mathematics

1 answer:

dusya [7]3 years ago

8 0

Hello!

The midpoint separates two equal distances,

This means that AB = BC

So lets type of the equation to solve for x:

2x + 7 = 5x -14

Lets add 14 on both sides.

2x + 21 = 5x

Lets subtract 2x on both sides.

21 =3x

Lets divide 3 by both sides

x = 7

AB= 21

2(7) + 7

14 + 7

BC = 21

5(7) - 14

35 - 14

AC = 42

21 + 21 = 42

I hope this helps, Have a great day!!

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Find the local extreme values of the function f(x, y) = xy - x2 - y2 - 3x - 3y + 12

aev [14]

$f(x,y)=xy-x^2-y^2-3x-3y+12$

First compute the first-order partial derivatives and find the critical points.

$f_x=y-2x-3$
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Both first order derivatives vanish at $(x,y)=(-3,-3)$ .

Computing the Hessian, we get

$\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}-2&1\\1&-2\end{bmatrix}$

We have $\det\mathbf H(x,y)=3>0$ , which means $(-3,-3)$ is an extremum of $f(x,y)$ . Since $f_{xx}(-3,-3)=-2$ , this extremum is a local maximum of $f(x,y)$ with a value of 21.

5 0

3 years ago

Can someone help me I will mark u brilliant

Ede4ka [16]

Answer:

Hello! answer: 20

Step-by-step explanation:

1/8 × 20 = 2 1/2 So the answer is 20 HOPE THAT HELPS!

3 0

3 years ago

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