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Andre45 [30]
2 years ago
11

PLEASE HURRY WILL GIVE BRAINLIST ​

Mathematics
2 answers:
ANEK [815]2 years ago
8 0
67 x=67
Explaination
NARA [144]2 years ago
4 0

Answer:

the answer is five

Step-by-step explanation:

I have provided a photo to show you how I got got.

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Could Someone PLEASE help me with this it is stumping me.
Bess [88]

9514 1404 393

Answer:

  G  45

Step-by-step explanation:

If Z is the circumcenter, it is equidistant from the vertices T, U, V. That is, ΔZUV is an isosceles triangle and Y is the midpoint of UV.

If Y is the midpoint of UV, then UY = VY = 22.5, and UV = UY +VY = 45.

The length of UV is 45.

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2 years ago
HELP PLS - QUIZ AND IM VERY CONFUSED
Katarina [22]
Ms Girl we on the Same Note tbh
5 0
3 years ago
Plsss help i’ll give brainliest if you give a correct answer
Ymorist [56]

Answer:

300

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.
den301095 [7]

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

              \texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²

8 0
3 years ago
Use the formula v=5to the third power where v is the volume and s is the edge length of the cube to solve this problem what is t
elena-s [515]
If I'm really it correctly, V = 5^3
v = s^3
s = 5
V = 5*5*5
V = 25*5 That's 2 fives multiplied together.
V = 125 cubic units. 
5 0
3 years ago
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