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svp [43]
2 years ago
9

Which of the following statements is TRUE? You cannot choose the Economy Plan if you have a family. You can choose to opt out of

any health care, vision coverage, and/or dental coverage included in the Standard Plan described in the Medical Plan documents. Neither plan covers visits to Urgent Care Facilities. Because both plans are a "grandfathered health plan" there is a $0 office copay
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
3 0

The statement which is true is; You can choose to opt out of any health care, vision coverage, and/or dental coverage included in the Standard Plan described in the Medical Plan documents.

<h3>Medical plans</h3>

In partial fulfillment of exercising one's human rights, an individual can choose to opt out of any healthcare, vision coverage, and/or dental coverage included in the Standard Plan described in the Medical Plan documents.

However, there are consequences for not having medical plans.

Read more on medical plans;

brainly.com/question/25793763

You might be interested in
The average amount parents and children spent per child on back-to-school clothes in Autumn 2010 was $527. Assume the standard d
Ad libitum [116K]

Answer: a. 0.14085

b. 3.826 x 10^{-3}

c.  0.5437

d. 0.0811  

Step-by-step explanation:

Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , \mu = $527

Given standard deviation , \sigma = $160

Let X = amount spent on a randomly selected child

Also Z = \frac{X-\mu}{\sigma}

a. Probability(X>$700) = P(\frac{X-\mu}{\sigma} > \frac{700-527}{160}) = P(Z>1.08125) = 0.14085 {Using Z % table}

b. P(X<100) = P( Z < \frac{100-527}{160}) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x 10^{-3}

c. P(450<X<700) = P(X<700) - P(X<=450)

   P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592

   P(X<=450) = P(Z<= \frac{450-527}{160}) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155

   So final   P(450<X<700) =  0.8592 - 0.3155 = 0.5437

d. P(X<=300) = P(Z<= \frac{300-527}{160}) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811                                                                        

All the above probabilities are calculated using Z % table along with interpolation between two values.

7 0
3 years ago
Jenna got 12, or 3/5, of her answers on the test right. How many questions were on the test?
aniked [119]

Answer:

20

Step-by-step explanation:

12 times 5/3 =60/3=20

6 0
2 years ago
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
2 years ago
A researcher conducted an experiment to investigate the effects of working in crowded versus uncrowded conditions on the job sat
Artyom0805 [142]

In a research of investigating the effects of working in crowded versus uncrowded conditions on the job satisfaction of employees in a variety of work setting , working is a depending variable and crowding is an independent variable.

Given aim of the research is to investigate the effects of working in crowded conditions and uncrowded conditions.

We know that depending variable is a variable whose value is dependent on the other variable. Independent variable is a variable whose value does not dependent on the other variables.

In the given question working may be affected negatively in crowded environment means there will be less work in crowded environment and more work in uncrowded environment.

Hence the depending variable in research is working.

Learn more about depending variables at brainly.com/question/25223322

#SPJ4

4 0
2 years ago
How can i get the volume??
Paladinen [302]
Length times width times height gives you the volume of things
6 0
3 years ago
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