Hello!
Recall that:
![\sqrt[z]{x^{y} }](https://tex.z-dn.net/?f=%5Csqrt%5Bz%5D%7Bx%5E%7By%7D%20%7D)
is equal to 
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
Add -3.4 to both sides
-9.3 = y
Hope this helps!
What was the instructions given
Answer: The line already goes thru 6,2 because 6=1/3(2) So the equation is y=1/3x
Step-by-step explanation:
(y-2)=1/3(x-6)
y-2=1/3x-6/3
y=1/3x
