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drek231 [11]
3 years ago
6

Jeff made a chocolate pie on Monday. He and a friend ate half of it the next day. On Wednesday, they ate one half of the remaini

ng pie. How Much of the pie is left on Thursday?
A: 1/8
8: 1/4
C:0
D: 1/2
Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

If you break down the problem, it says that they ate half of the pie, which leaves one half left. if they eat half of that, you get 1/4.

Hope i helped!

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Fofino [41]

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3 0
3 years ago
Can someone help me please!
Pani-rosa [81]

Answer:

.1123 This is my guess, I'm not 100 percent sure though

Step-by-step explanation:

Add them all together, and then put 11 over it

11/98

Divide and this is .1122448979591837

If you round it ends up being

.1123

7 0
3 years ago
Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo
jeka94

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)

The maxterm is the product of the complements.

F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

3 0
3 years ago
(-3) ÷ (-2) + 8 HELPPP​
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Answer:

9.5

Step-by-step explanation:

(-3) ÷ (-2) = 1.5

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Answer:

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