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3 years ago

Fre.e po.ints have a great day

Mathematics

2 answers:

frozen [14]3 years ago

8 0

Answer:

thanks and I like your pfp

il63 [147K]3 years ago

3 0

Answer:

thanks

Step-by-step explanation:

You might be interested in

What's the inverse of f(x) = x-3/5

Degger [83]

Answer:

y = x + 3/5

Step-by-step explanation:

1. Label this function 'y': y = x - 3/5

2. Interchange x and y: x = y - 3/5

3. Solve this for y: y = x + 3/5

This last result is the inverse of the given function.

4 0

3 years ago

Read 2 more answers

Look at this system of equations.<br> 2x +5 =9.5<br> 3x + 5y =10.5<br> What is the value of x+y

stiv31 [10]

Answer:

x = 2.25 y = 0.75

Step-by-step explanation:

2x = 9.5- 5

2x = 4.5

x = 4.5 ÷ 2

x = 2.25

know we now what is x so in the second one we evaluate x

3(2.25) + 5y = 10.5

6.75 + 5y = 10.5

5y = 10.5- 6.75

5y = 3.75

y = 3.75 ÷ 5

y = 0.75

that's it !

if you want to check your answer you can evaluate x and y so it will be like

2×2.25 + 5

= 4.5 + 5 = 9.5

and

3× 2.25 +5×0.75

= 6.75 + 3.75 = 10.5

6 0

3 years ago

A certain country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The

mash [69]

Answer:

$\bf x(t)=10(1-e^{-0.005*t})$

Step-by-step explanation:

The differential equation

$\bf \displaystyle\frac{dx}{dt}=0.005(10-x)$

can be solved by separation of variables. Write the equation as

$\bf \displaystyle\frac{dx}{10-x}=0.005dt$

Integrate on both sides

$\bf \int\displaystyle\frac{dx}{10-x}=\int0.005dt\Rightarrow -ln(10-x)=0.005t+C\Rightarrow\\\\\Rightarrow ln(10-x)^{-1}=0.005t+C\Rightarrow (10-x)^{-1}=e^{0.005t}e^C$

where C is a constant.

$\bf e^C$ is also a constant and we will keep calling it C, (there is no reason to change the letter). We have then

$\bf (10-x)^{-1}=Ce^{0.005t}\Rightarrow \displaystyle\frac{1}{10-x}=Ce^{0.005t}\Rightarrow 10-x=\displaystyle\frac{1}{Ce^{0.005t}}\Rightarrow\\\\\Rightarrow x(t)=10-(1/C)e{-0.005t}$