C=2pr, r=c/(2p)
a=pr^2, using r found above we get:
a=p(c^2/(4p^2))
a=(c^2)/(4p), since c=106.76 and we approximate pi as 3.14
a=(106.76^2)/(4*3.14)
a=11612.2176/12.56 cm^2
a≈924.54 cm^2 (to nearest one-hundredth of a square cm)
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Step-by-step explanation:
The given is,
Kuroshio Sea tank is 27m long, 35m wide and 10m deep.
Step:1
Sea tank looks like a rectangular prism,
Formula to calculate the volume of rectangular prism,
.............................(1)
Where, w - Width of the rectangular prism
h - Height or depth of the rectangular prism
l - Length of the rectangular prism
From given,
w = 35 meters
l = 27 meters
h = 10 meters
Equation (1) becomes,



Volume of the sea tank, V = 9450 Cubic meters
Result:
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Answer:
40 years
Step-by-step explanation:
He was also the first Roman Emperor
Answer:
-20
Step-by-step explanation:
it basically -14-6
Answer:
Step-by-step explanation:
Could you please show us the graph so we could answer as correct as possible? Thanks!