Answer:
a. Bisector is at point M
b. 
Step-by-step explanation:
Question is not well formatted:
Given
Solving (a): The segment bisector
From the given parameters above
We have AM and MB
The common point in AM and MB is M;
This indicates that the bisector is at point M
Solving (b): The value of AB
First we need to determine the value of x
Because M is the point of bisector;
Collect Like Terms
Solve for x
Next is to determine the value of AB using
Collect Like Terms
Substitute 12 for x
I think it may be 2 but I’m not too sure about it
Step-by-step explanation:
Coordinates of Point R = (0, y).
We have PR = QR.
=> (-2 - 0)² + (6 - y)² = (9 - 0)² + (3 - y)².
=> 4 + (6 - y)² = 81 + (3 - y)²
=> y² - 12y + 40 = y² - 6y + 90
=> 6y + 50 = 0
=> y = -25/3.
Hence the answer is (0, -25/3).
Coordinates of Point S = (x, 0).
We have PS = QS.
=> (-2 - x)² + (6 - 0)² = (9 - x)² + (3 - 0)²
=> (-2 - x)² + 36 = (9 - x)² + 9
=> x² + 4x + 40 = x² - 18x + 90
=> 22x = 50
=> x = 25/11.
Hence the answer is (25/11, 0).
Answer: 12
Step-by-step explanation:
3 x 4 = 12
