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ehidna [41]
3 years ago
6

A candy company manufactures bags of colorful candies. The company reports that it makes 10% each of green and red candies, and

20% each of yellow, blue, and orange candies. The rest of the candies are brown If you pick a candy at random, what is the probability that it is either red or yellow?
Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

30% probability that it is either red or yellow

Step-by-step explanation:

We have that:

10% of the candies are green

10% of the candies are red

20% of the candies are yellow

20% of the candies are blue

20% of the candies are orange.

The rest is brown. The percentage of brown candies is not important to this problem.

If you pick a candy at random, what is the probability that it is either red or yellow?

10% are red

20% are yellow

10 + 20 = 30%

30% probability that it is either red or yellow

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The given inequality is:

|-8x+24| \leq 16

This inequality can be divided in two parts as:

a) -16 \leq -8x +24
b) -8x + 24 \leq 16

Solving part a:

-16 \leq -8x+24 \\  \\ 
-40 \leq -8x \\  \\ 
5 \geq x \\ 
or \\ 
x \leq 5

Solving part b:

-8x+24 \leq 16 \\  \\ 
-8x \leq -8 \\  \\ 
x \geq 1

Therefore, the solution to the given inequality is x \leq 5 and x \geq 1. Combining both the ranges we get the solution: 1 \leq x \leq 5.

In interval notation, this solution can be expressed as [1,5]
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