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ehidna [41]
3 years ago
6

A candy company manufactures bags of colorful candies. The company reports that it makes 10% each of green and red candies, and

20% each of yellow, blue, and orange candies. The rest of the candies are brown If you pick a candy at random, what is the probability that it is either red or yellow?
Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

30% probability that it is either red or yellow

Step-by-step explanation:

We have that:

10% of the candies are green

10% of the candies are red

20% of the candies are yellow

20% of the candies are blue

20% of the candies are orange.

The rest is brown. The percentage of brown candies is not important to this problem.

If you pick a candy at random, what is the probability that it is either red or yellow?

10% are red

20% are yellow

10 + 20 = 30%

30% probability that it is either red or yellow

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Ireland has a 23% VAT (value-added tax, similar to a sales tax). How much will the VAT be on a purchase of a €250 item?
Maurinko [17]
€250 x 1.23 (123%) = €307.50

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5 0
3 years ago
Read 2 more answers
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
Jimmy set his score for his math test. After the math teacher returnee his paper to him, he realized that if he increased his ta
mixer [17]
When ever you have percentages, it should be helpful to bear in mind you can express them as multipliers. In this case, it will be helpful.
So, if we let:
a = test score
b = target score
then, using the information given:
a = 1.1b + 1
a = 1.15b - 3
and we get simultaneous equations.
'1.1' and '1.15' are the multipliers that I got using the percentages. Multiplying a value by 1.1 is the equivalent of increasing the value by 10%. If you multiplied it by 0.1 (which is the same as dividing by 10), you would get just 10% of the value.
Back to the simultaneous equations, we can just solve them now:
There are a number of ways to do this but I will use my preferred method:
Rearrange to express in terms of b:
a = 1.1b + 1
then b = (a - 1)/1.1
a = 1.15b - 3
then b = (a + 3)/1.15
Since they are both equal to b, they are of the same value so we can set them equal to each other and solve for a:
(a - 1)/1.1 = (a + 3)/1.15
1.15 * (a - 1) = 1.1 * (a + 3)
1.15a - 1.15 = 1.1a + 3.3
0.05a = 4.45
a = 89

8 0
3 years ago
Need help!!<br> will give brainlist
prisoha [69]
White, 7/10= 14/20
It has the largest chance of being selected at random
5 0
3 years ago
Anybody know the answer?
expeople1 [14]
Y=x-2+3
I put x-2 because when graphing it's the opposite so it would technically be x+2
Then the +3 for the y chords which go up by 3 ! if this is wrong then try Y= (x-2)+3
8 0
3 years ago
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