All categories

3 years ago

What is the rate of change of y=-50+31

Mathematics

1 answer:

leonid [27]3 years ago

4 0

Hey there!

Guide:

• Negatives are on the LEFT side of the number line

• Positives are on the RIGHT side of the number line.

• Negatives are BELOW 0 (less than 0)

• Positives are ABOVE 0 (more than 0)

• You have to take the value of the LARGER number.

• If your LARGER number is a negative number then your result will be a negative.

• If your LARGER is a positive number then your result will be a positive

• Negative & Negative = Positive

• Negative & Positive = Negative

• Positive & Positive = Positive

• Positive & Negative = Negative

y = -50 + 31

• So, you start from -50 and go UP 31 spaces to the right because “31” is a positive number.. once when you have moved UP your 31 spaces you have reached your answer for this given equation

y = -50 + 31

y = -19

Therefore, your answer is: y = -19

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

You might be interested in

The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form

kolbaska11 [484]

h=(a)(sinC)=19(sin37)

That means h ≈11.43

Since c<h, There is no triangle

6 0

3 years ago

Read 2 more answers

1/2 of 2/3=1/2 of___third(s)=third(s)

Westkost [7]

13 * (12 - 3 38) = -2324 ≅ -0.9583333Calculation stepsConversion: 3 3/8 = 3 · 8 + 38 = 278Subtract: 12 - 278 = 1 · 42 · 4 - 278 = 48 - 278 = 4 - 278 = -238Multiple: 13 * (-238) = 1 · (-23)3 · 8 = -2324

4 0

3 years ago

Select the correct trigonometric ratios for angle 0

ratelena [41]

Answer:

A, D, and F

Step-by-step explanation:

First off, we're not given the hypotenuse's length, so let's use the Pythagorean Theorem to find it:

$1^2+3^2=c^2\\1+9=c^2\\10=c^2\\c=\sqrt{10}$

With that, we can refer to SOH-CAH-TOA to help us find sine, cosine, and tangent:

SOH (Sine = Opposite/Hypotenuse)

$\sin{\theta}=1/\sqrt{10}=\sqrt{10}/10$

CAH (Cosine = Adjacent/Hypotenuse)

$\cos{\theta}=3/\sqrt{10}=3\sqrt{10}/10$

TOA (Tangent = Opposite/Adjacent)

$\tan{\theta}=1/3$

From this, we can see that A matches up with sine, and we can eliminate B and C.

Cosecant, secant, and cotangent are all reciprocals of the three basic trig ratios:

$\csc{\theta}=1/\sin{\theta}=\sqrt{10}\\\sec{\theta}=1/\cos{\theta}=\sqrt{10}/3\\\cot{\theta}=1/\tan{\theta}=3$

D matches with cosecant, and F matches with cotangent, so the correct trig rations for θ are A, D, and F.

3 0

3 years ago

Mrs. Bowman designed the rug shown . If it costs 22$ per square footage to make, how much will Mrs. Bowman pay for the rug?

vazorg [7]

Just multiply 22 by the number it says.

7 0

3 years ago

Read 2 more answers

Solve for L: d= (LR_2)/(R_2+R_1

Lubov Fominskaja [6]

D= (LR_2)/(R_2+R_1)
d(R_2+R_1)= LR_2 
d(R_2+R_1)/(R_2)= L 
L= d(R_2+R_1)/(R_2) 

The answer I obtained is the same answer as the third choice. 

L= d(R_2+R_1)/(R_2) 
L= (R_2+R_1)d/(R_2) 
L= (R_2+R_1)(d)/(R_2) 
L= ((R_2+R_1)(d))/(R_2)

5 0

3 years ago