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damaskus [11]
3 years ago
11

Solve for L: d= (LR_2)/(R_2+R_1

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
D= (LR_2)/(R_2+R_1) 
<span>d(R_2+R_1)= LR_2 </span>
<span>d(R_2+R_1)/(R_2)= L </span>
<span>L= d(R_2+R_1)/(R_2) </span>

<span>The answer I obtained is the same answer as the third choice. </span>

<span>L= d(R_2+R_1)/(R_2) </span>
<span>L= (R_2+R_1)d/(R_2) </span>
<span>L= (R_2+R_1)(d)/(R_2) </span>
<span>L= ((R_2+R_1)(d))/(R_2)</span>
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B. Mercury, Venus, and Earth are the three planets closest to the sun. Would their combined distance from
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A=2 b=3 c=4<br><br> 1) ab - c =<br> 2) 6c - 2b=<br> 3) a + b - c + 5 =<br> 4) 7c - 2a =
bekas [8.4K]

Step-by-step explanation:

1)ab-c

=2(3)-4

=6-4

=2

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=6(4)-2(3)

=24-6

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7 0
4 years ago
Read 2 more answers
Match the following items by evaluating the expression for x = -2.
Sloan [31]

Answer:

1)  -4

2) -3

3) 1

4) -2

5) 4

Step-by-step explanation:

According to the information given in the exercise, the value of "x" is:

x = -2

Then:

1) You must substitute  x = -2 into the expresion x-2:

=(-2)-2

Now, you must evaluate:

=-4

2) You have to substitute the given value of "x" into the second expression:

x-1=(-2)-1

Finally, evaluating, you get the following result:

=-3

3) According to the Zero exponent Rule, any non-zero number with an exponent of zero is equal to 1.

Then, substituting x = -2 into the expression x^0 and then evaluating, you get:

x^0=(-2)^0=1

4) By definition:

 a^1=a

Then, substituting   x = -2 into x^1 and evaluating, you get:

x^1=(-2)^1=-2

5) Since:

 a^2=a*a

When you substitute the given value of "x" into the last expression and then  you evaluate, you get:

x^2=(-2)^2=(-2)(-2)=4

4 0
3 years ago
Please help me with this problem. How do I find x?
inysia [295]
Assuming that is 2 right triangles sharing a side
height^2 = 20^2 -7^2
height^2 = 400 - 49
height^2 = 351
height = <span> <span> <span> 18.7349939952 </span> </span> </span>
x^2 = 24^2 - <span>18.7349939952^2
x^2 = 576 -351
x^2 = 225
x = 15

</span>
7 0
3 years ago
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