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Mathematics

1 answer:

ololo11 [35]3 years ago

4 0

5,20,45 I sure that’s the correct answer

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Solve the inequality for x<br> -x+23<2-2(x-8)

lesya [120]

Answer:

inequality form: x<-5

Step-by-step explanation:

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2 years ago

What is the solution to the system of equations below?<br>2x+3y = 17<br>3x+6y= 30

brilliants [131]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+3y=17&\text{multiply both sides by (-2)}\\3x+6y=30\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-4x-6y=-34\\3x+6y=30\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-x=-4\qquad\text{change the signs}\\.\qquad x=4\\\\\text{put the value of x to the first equation:}\\\\2(4)+3y=17\\8+3y=17\qquad\text{subtract 8 from both sides}\\3y=9\qquad\text{divide both sides by 3}\\y=3$

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3 years ago

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If the mountain at a convergent plate boundary is growing at a rate of 1.6 mm per year, how much higher will it be in 50 years ?

Mrrafil [7]

The mountain will be at 80mm long in 50 years because 50 times 1.6mm equals 80

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2 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

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3 years ago

A video posted on the internet has gone viral, and the total number of views is increasing by 25% every hour. If the video curre

sergeinik [125]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &155000\\ r=rate\to 25\%\to \frac{25}{100}\dotfill &0.25\\ t=hours\dotfill &6\\ \end{cases} \\\\\\ A=155000(1 + 0.25)^{6}\implies A=155000(1.25)^6\implies A\approx 591278$

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2 years ago