Price of lunch of each, P = $ 18.45/3 = $ 6.15 .
Now, number of people that can eat the barbecue at a budget of $1850.00 is:
![n=\dfrac{1850}{6.15}\\\\n=300.81](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B1850%7D%7B6.15%7D%5C%5C%5C%5Cn%3D300.81)
Therefore, Mr. Gaines afford maximum 300 people to feed on a budget of $1850.00 .
Hence, this is the required solution.
Since the order of choosing out students to hand out papers doesnt matter because the paper handed is just the same and that the purpose or task of each student is just the same, combination should be used. Otherwise, when the order is based on ranking of students for example, permutation is used. answer is true
Answer:
![A(-3,2)\: B(-1,-2)\: C(1,3)](https://tex.z-dn.net/?f=A%28-3%2C2%29%5C%3A%20B%28-1%2C-2%29%5C%3A%20C%281%2C3%29)
![A=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=A%3D1%2F2%5Bx_1%28y_2-y_3%29%2Bx_2%28y_3-y_1%29%2Bx_3%28y_1-y_2%29%5D)
![=1/2[-3(-2-3)(+1(3-2)+1(2-(-2))]](https://tex.z-dn.net/?f=%3D1%2F2%5B-3%28-2-3%29%28%2B1%283-2%29%2B1%282-%28-2%29%29%5D)
![=1/2(15+1+4)](https://tex.z-dn.net/?f=%3D1%2F2%2815%2B1%2B4%29)
![=1/2(20)](https://tex.z-dn.net/?f=%3D1%2F2%2820%29)
![=10](https://tex.z-dn.net/?f=%3D10)
![ANSWER: 10 ~units^{2}](https://tex.z-dn.net/?f=ANSWER%3A%2010%20~units%5E%7B2%7D)
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hope it helps...
have a great day!!
Find the reciprocal of the second fraction: -9/4, and multiply it instead of dividing.
2/3 x -9/4 = -18/12. By reducing it’ll be -3/2, or -1 1/2 in mixed form.
The answer is C. y < 2 - 1/2x