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3 years ago

What is the equation of a line in slope intercept form, given that the slope of the line is 1 and a point on

Mathematics

1 answer:

choli [55]3 years ago

4 0

Answer:

y= -x +2

Step-by-step explanation:

y-y1 = m(x-x1)

y - 0 = 1(x - (-2))

y = -x + 2)

y = x + 2.

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3 years ago

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3 years ago

What is the diffinition of qutionmbra

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3 years ago

Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]

Molodets [167]

For convenience sake, I will let $y=f(x)=9e^{x}\sin x$

First, we evaluate the function at the endpoints of the interval.

$f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0$

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

$f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)$

Setting this equal to 0,

$9e^x (\cos x+\sin x)=0$

Since $9e^x > 0$ , we can divide both sides by $9e^x$ .

$\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}$

$f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}$

So, the absolute minimum is $\boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)}$ and the absolute minima are $\boxed{(0,0), (\pi, 0)}$

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1 year ago

Tell whether the angles are vertical or adjacent. Then find the measure of x.

xxTIMURxx [149]

Answer:

adjacent. x=55

Step-by-step explanation:

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2 years ago

Read 2 more answers