Answer:
and
do not lie on the line
Step-by-step explanation:
Given

Required
Determine which points that are not on the line
First, we need to determine the slope (m) of the line:

Where


So;



Next, we determine the line equation using:

Where


becomes


To determine which point is on the line, we simply plug in the values of x to in the equation check.
For 
and 
Substitute 4 for x and 2 for y in 



<em>This point is on the graph</em>
<em></em>
For 
and
Substitute 4 for x and 3 for y in 



<em>This point is not on the graph</em>
<em></em>
For 
and 
Substitute 7 for x and 2 for y in 



<em></em>
<em>This point is not on the graph</em>
<em></em>
<em></em>
<em></em>
<em></em>
and<em> </em>
<em></em>
<em>Substitute </em>
<em> for x and </em>
<em> for y in </em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em>This point is on the graph</em>
Answer:
He has 30 penguins and 10 cats.
Step-by-step explanation:
Let's define the variables:
C = number of cats.
P = number of penguins.
We know that he has a total of 40 pets, then:
C + P = 40
We also know that the total heads (40 heads, each animal has one) plus the number of wings (P*2, each penguin has 2) is equal to the number of feet of his pets (4*C + 2*P, because each cat has 4 paws, and each penguin has 2)
Then we have the equation:
40 + 2*P = 4*C + 2*P
Notice that in the second equation we have the term 2*P in both sides of the equation, then we can just subtract 2*P in both sides to get:
(40 + 2*P) - 2*P = 4*C + 2*P - 2*P
40 = 4*C
Now with this, we can find the value of C.
40/4 = C = 10
Then he has 10 cats.
Now we can replace this in the equation:
P + C = 40
to find the value of P
P + 10 = 40
P = 40 - 10 = 30
P = 30
He has 30 penguins.
Answer:
-17
Step-by-step explanation:
So you take -6 and subtract another 11, that gives you negative 17.
Hope This Helps! If it doesn’t let me know and I can explain it more in depth.
6;9 = 2;3
thats one only hope it help a little
Hi!!
The answer to your question is asking us to make an algerbraic equation for this situation.
H = 5V
Also, H + V = 52,000. H and V can then be solves by solving the 2 equations.
The results are 43,333 and 8,667
If you still don't understand message me
If you do plz brainlest