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PSYCHO15rus [73]
3 years ago
5

12 men working 8 hours a day complete a piece of work in 10 days to complete a the same work in 8 days working 15 hours a days t

he number of men required is
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

12 men : 8 hours : 10 days


// Find if every man works 1 hour

12 x 8 men : 1 hour : 10 days

96 men : 1 hour : 10 days


//Find if every man works 15 hours

96 ÷ 15 men : 15 hours : 10 days

6.4 men : 15 hours : 10 days


//Find if every man works 1 day

6.4 x 10 men : 15 hours : 1 day

64 men : 15 hours : 1 day


//Find if every man works 8 days

64 ÷ 8 men : 15 hours : 8 days

8 men : 15 hours : 8 days


Answer: 8 men is needed

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Degger [83]
D is the correct answer 
3 0
3 years ago
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Escribe la posición del móvil si el diámetro de la trayectoria es de 10 m y la distancia recorrida es de 190 m
lions [1.4K]

Step-by-step explanation:

La posici´on de una part´ıcula que se mueve unidimensionalmente esta definida por la ecuaci´on:

x(t) = 2t

3 − 15t

2 + 24t + 4 donde 0x

0 y

0

t

0

se expresan en metros y segundos respectivamente. Determine:

a. ¿Cu´ando la velocidad es cero?

b. La posici´on y la distancia total recorrida cuando la aceleraci´on es cero.

Soluci´on:

a. Recordemos que:

v(t) =

dx

dt =

d

dt(2t

3 − 15t

2 + 24t + 4) = 6t

2 − 30t + 24

Sea t

0

el tiempo en que la velocidad se anula, entonces v(t

0

) = 0.

De este modo:

0 = v(t

0

) = 6(t

0

)

2 − 30(t

0

) + 24 = 6[(t

0

)

2 − 5(t

0

) + 4] = 6[(t

0

) − 4][(t

0

) − 1]

As´ı tenemos que:

t

0

1 = 4, t

0

2 = 1

De este modo, tenemos que la velocidad se anula al primer segundo y a los cuatro segundos.

b. Recordemos que:

a(t) =

dv

dt =

d

dt(6t

2 − 30t + 24) = 12t − 30

Ahora sea t

0

el instante en que la aceleraci´on se anula, entonces a(t

0

) = 0

Ahora:

0 = a(t

0

) = 12t

0 − 30

As´ı tenemos que: t

0 =

30

12 =

5

2

Por lo tanto, la posici´on en este instante es:

x(t

0

) = x

5

2

= 2

5

2

3 − 15

5

2

2 + 24

5

2

+ 4 = 125

4 − 3

125

4 + 60 + 4 = −2

125

4 + 64 = −

125

2 +

128

2 =

3

2

De este modo, la posici´on de la part´ıcula cuando la aceleraci´on es cero es de 3

2 metros.

Adem´as la distancia total recorrida esta dada por:

distancia = |x(t

0

) − x(0)| = |

3

2 − 4| =

5

2

Finalmente la distancia total recorrida es: 5

5 0
2 years ago
( a^5 ⋅ 2^3 )^3 = ?<br> Please help and explain.
vlabodo [156]

Answer: 512a^{15}

Step-by-step explanation:

(a^5*2^3)^3

First, lets solve the inside of the parenthesis

(a^5*8)^3

Now, distribute the power of 3 to both terms. Remember taking a power of an exponent is like multiplying them (in this case (a^5)^3=a^{15}

a^{15}*512

Simplify

512a^{15}

5 0
2 years ago
Write an equation in standard form of the line that has x-intercept 1 and y-intercept 4?
GREYUIT [131]

Answer:d

Step-by-step explanation:

c and b are out and d makes more sense than a

3 0
2 years ago
Jocelyn walks her dog 5 days each week. Each walk is 24 miles long.
Lynna [10]

Answer:

Total distance covered each week is 11\frac{1}{4}\ miles

Step-by-step explanation:

Given

Days = 5 days

Distance = 2\frac{1}{4} miles

Required

Determine the total distance covered in a week

To do this, we simply multiply distance by number of days.

Total\ distance = distance * days

Total\ distance = 2\frac{1}{4} * 5

Convert to improper fraction

Total\ distance = \frac{9}{4} * 5

Total\ distance = \frac{9 * 5}{4}

Total\ distance = \frac{45}{4}

Total\ distance = 11\frac{1}{4}

Hence, the total distance covered each week is 11\frac{1}{4}\ miles

6 0
3 years ago
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