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andriy [413]
3 years ago
9

Integral of 1/(x^2-x+1) ​

Mathematics
1 answer:
Lunna [17]3 years ago
6 0

\boxed{\sf \displaystyle{\int}x^ndx=\dfrac{x^{n+1}}{n+1}}

\\ \sf\longmapsto \displaystyle{\int}\dfrac{1}{x^2-x+1}

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-x^{-1}+1

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-\displaystyle{\int}x^{-1}+\displaystyle{\int}1

\\ \sf\longmapsto \dfrac{x^{-2+1}}{-2+1}-\dfrac{x^{-1+1}}{-1+1}+1

\\ \sf\longmapsto \dfrac{x^{-1}}{-1}-\dfrac{x^0}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\dfrac{1}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\infty+1

\\ \sf\longmapsto \infty

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lorasvet [3.4K]

Answer:

'Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

10% = 10/100 = 10 ÷ 100 = 0.1.

100% = 100/100 = 100 ÷ 100 = 1.

Increase the number by 10% of its value.

Percentage increase = 10% × 2,880

New value =

2,880 + Percentage increase =

2,880 + (10% × 2,880) =

2,880 + 10% × 2,880 =

(1 + 10%) × 2,880 =

(100% + 10%) × 2,880 =

110% × 2,880 =

110 ÷ 100 × 2,880 =

110 × 2,880 ÷ 100 =

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Calculate absolute change (actual difference)

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Step-by-step explanation:

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Step-by-step explanation:

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Kaylis [27]

Answer:

2398 = 2000

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Step-by-step explanation:

Given

2398

56254

71563

33021

9645

Required

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2398

Highest place value here is thousand.

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Highest place value here is ten thousand.

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71563

Highest place value here is ten thousand.

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71563 = 70000 when approximated

33021

Highest place value here is ten thousand.

So:

33021 = 30000 when approximated

9645

Highest place value here is ten thousand.

So:

9645 = 10000 when approximated

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3 years ago
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First, let's add the two from both sides.
y + 2 = 3x - 2 + 2
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And now, flip both sides around so it looks nicer.
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