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pishuonlain [190]
2 years ago
11

If a^(b/4) = 16 for positive integers a and b, what is one possible value of b?.

Mathematics
1 answer:
Verizon [17]2 years ago
5 0

Answer:

Step-by-step explanation:

a^{(\dfrac{b}{4})} = 16\\\\\\Both \ sides \ raise \ to \ 4\\\\(a^{\dfrac{b}{4}})^{4} = 16^{4}\\\\a^{\dfrac{b}{4}*4}=16^{4}\\\\a^{b}=16^{4}

b = 4

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If they are, the perceptive is a bit different. Your expression gives the likelihood that a particular set of j balls goes into the last urn and the other n−j balls into the other urns. But there are (nj) different possible sets of j balls, and each of them the same probability of being the last insides of the last urn, so the total probability of completing up with exactly j balls in the last urn is if the balls are different.


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Step-by-step explanation:

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Is 19 2/9 a integer​
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3 0
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Please help me!
Zigmanuir [339]

Answer:

s = 14

Step-by-step explanation:

Step 1: Combine like terms.

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2 years ago
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