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Shkiper50 [21]
2 years ago
7

How to rename 3/12 I forgot

Mathematics
2 answers:
Kobotan [32]2 years ago
8 0
0.25 is 3/12 simplified
GaryK [48]2 years ago
5 0
It would be 0.25 for the answer
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Tony bought a video game for $15.13. He gave the clerk a $20 bill. Which of the following could be the change he received?
Tanya [424]

Answer:

$4.87

Step-by-step explanation:

20 - 15.13 = 4.87

5 0
2 years ago
What is the quotient of -1/8 and - 1/3
eimsori [14]

Answer:

Step-by-step explanation:

(-1/8)/(-1/3) = (-1/8)×(3/-1) = (-1)(3)/(8)(-1) = -3/-8 = 3/8

3 0
3 years ago
A 12 inch candle and an 18 inch Candle are lit at 6 p.m. The 12 inch candle burns 0.5 inches every hour. The 18 inch candle burn
Stella [2.4K]
18 - 2H = 12 - .5H
Combine the variables
18 - 2H + .5H = 12 - .5H + .5H
18 - 1.5H = 12
Combine the whole numbers
18 - 18 - 1.5H = 12 - 18
-1.5H = -6
Divide by -1.5
-1.5H/-1.5 = -6 / -1.5
H = 4
The answer is 4 hours
7 0
3 years ago
Question 3 (Multiples and Factors] Three numbers are given below. Use prime factorisation to determine the HCF and LCM 1848 132
Ilia_Sergeevich [38]

Prime factorization involves rewriting numbers as products

The HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

<h3>How to determine the HCF</h3>

The numbers are given as: 1848, 132 and 462

Using prime factorization, the numbers can be rewritten as:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

The HCF is the product of the highest factors

So, the HCF is:

HCF = 2 * 3 * 11

HCF = 66

<h3>How to determine the LCM</h3>

In (a), we have:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

So, the LCM is:

LCM = 2^3 * 3 * 7 * 11

LCM  = 1848

Hence, the HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

Read more about prime factorization at:

brainly.com/question/9523814

4 0
2 years ago
Pls help dis is due tomorrow n I have a science project also due so pls help me
pantera1 [17]
List A
4+4y=8y
4 (y-1)= 4
4y+1=5y

List B
4y-4=y
4 (y+1)=5y
1+4y=5y
5 0
3 years ago
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