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irina1246 [14]
3 years ago
14

Need help asap!!!!!!!

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

a) Linear function

b) Linear function

c) Exponential function

d) Exponential function

Step-by-step explanation:

a) The number of hours in a day increases constantly with 60 minute intervals

b) Constant speed = same distance traveled per given time - so it's linear

c) If a population doubles every y years, it means that the population is being raised exponentially - not at a constant rate, but more each year

d) Same as c

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C

Step-by-step explanation:

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3 years ago
Find KL and show work
MissTica

Answer:

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Intersecting Secants Theorem</u>

If two secant segments are drawn to the circle from one exterior point, the product of the measures of one secant segment and its external part is equal to the product of the measures of the other secant segment and its external part.

From inspection of the given diagram:

  • M = Exterior point
  • MK = secant segment and ML is its external part
  • MS = secant segment and MN is its external part

Therefore:

⇒ ML · MK = MN · MS

Given:

  • MK = (x + 15) + 6 = x + 21
  • ML = 6
  • MS = 7 + 11 = 18
  • MN = 7

Substituting the given values into the formula and solving for x:

⇒ ML · MK = MN · MS

⇒ 6(x + 21) = 7 · 18

⇒ 6x + 126 = 126

⇒ 6x = 0

⇒ x = 0

Substituting the found value of x into the expression for KL:

⇒ KL = x + 15

⇒ KL = 0 + 15

⇒ KL = 15

6 0
2 years ago
Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
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