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Lesechka [4]
3 years ago
9

A farmer has a house at the point (0, 0). He has a corn field that can be found by driving 1 unit up, 2 units right, 3 units dow

n, and then 3 units right. If he instead walks diagonally to his corn field, how far has he gone? Round to 2 decimal places.
Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0

Answer:

73.97

Step-by-step explanation:

lubasha [3.4K]3 years ago
7 0
73.97 should be the answer
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Answer the following:
bija089 [108]

Answer:

Penperdocular

Step-by-step explanation:

7 0
3 years ago
How do you find the length of an arc
marysya [2.9K]
The total length around the circle = 2 pi r = 2*pi*16 = 32 pi 

Total degrees around the circle = 360 so 

length of the arc of measure 270  = 32 pi * 270/360 =  24 pi  units

or 75.40 units to the nearest hundredth
3 0
3 years ago
What is 6x – 8 = 4 written as a system? y = 6x – 8 y = –4 y = 6x – 8 y = 4 y = –6x + 8 y = 4
mestny [16]

6x – 8 = 4 written as a system. Hence second option is correct

<u>Solution:</u>

Given, equation is 6x – 8 = 4.

We have to find the equivalent system from given options.

First let us solve given equation, 6x – 8 = 4 ⇒ 6x = 4 + 8 ⇒ 6x = 12 ⇒ x = 2

Now, let us solve one by one option ,so that when we get above solution, that is correct option.

  • y = 6x – 8 and y = -4 ⇒ put y = -4 in y = 6x – 8 ⇒ 6x – 8 = -4 ⇒ 6x = 8 – 4

⇒ 6x = 4 ⇒ x ≠ 2, wrong option

  • y = 6x – 8 and y = 4 ⇒ put y = 4 in y = 6x – 8 ⇒ 6x – 8 = 4 ⇒ 6x = 8 + 4 ⇒ 6x = 12 ⇒ x = 2, right option.
  • y = -6x + 8 and y = 4 ⇒ put y = 4 in y = -6x + 8 ⇒ -6x + 8 = 4 ⇒ 6x = 8 – 4 ⇒ 6x = 4 ⇒ x ≠ 2, wrong option

hence, second option is correct.

6 0
3 years ago
Read 2 more answers
Michael and his brother eric both live 5 miles from the park. If michael rides his bike at an average of 12 mph and eric rides h
ExtremeBDS [4]

Answer:5 min I think

Step-by-step explanation: 5 min I think

6 0
3 years ago
Can someone thoroughly explain this implicit differentiation with a trig function. No matter how many times I try to solve this,
Anton [14]

Answer:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

Step-by-step explanation:

So we have the equation:

\tan(x-y)=\frac{y}{8+x^2}

And we want to find dy/dx.

So, let's take the derivative of both sides:

\frac{d}{dx}[\tan(x-y)]=\frac{d}{dx}[\frac{y}{8+x^2}]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[\tan(x-y)]

We can use the chain rule, where:

(u(v(x))'=u'(v(x))\cdot v'(x)

Let u(x) be tan(x). Then v(x) is (x-y). Remember that d/dx(tan(x)) is sec²(x). So:

=\sec^2(x-y)\cdot (\frac{d}{dx}[x-y])

Differentiate x like normally. Implicitly differentiate for y. This yields:

=\sec^2(x-y)(1-y')

Distribute:

=\sec^2(x-y)-y'\sec^2(x-y)

And that is our left side.

Right Side:

We have:

\frac{d}{dx}[\frac{y}{8+x^2}]

We can use the quotient rule, where:

\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}

f is y. g is (8+x²). So:

=\frac{\frac{d}{dx}[y](8+x^2)-(y)\frac{d}{dx}(8+x^2)}{(8+x^2)^2}

Differentiate:

=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

And that is our right side.

So, our entire equation is:

\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

To find dy/dx, we have to solve for y'. Let's multiply both sides by the denominator on the right. So:

((8+x^2)^2)\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}((8+x^2)^2)

The right side cancels. Let's distribute the left:

\sec^2(x-y)(8+x^2)^2-y'\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy

Now, let's move all the y'-terms to one side. Add our second term from our left equation to the right. So:

\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy+y'\sec^2(x-y)(8+x^2)^2

Move -2xy to the left. So:

\sec^2(x-y)(8+x^2)^2+2xy=y'(8+x^2)+y'\sec^2(x-y)(8+x^2)^2

Factor out a y' from the right:

\sec^2(x-y)(8+x^2)^2+2xy=y'((8+x^2)+\sec^2(x-y)(8+x^2)^2)

Divide. Therefore, dy/dx is:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)+\sec^2(x-y)(8+x^2)^2}

We can factor out a (8+x²) from the denominator. So:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

And we're done!

8 0
3 years ago
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