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shepuryov [24]
3 years ago
13

Kim worked these hours last week: Monday 8, Tuesday 7.5, Wednesday 6.5, Thursday 3, and Friday 9 hours. She is paid $20.25 per h

our. (a) How many hours did Kim work last week? (b) What was her gross pay for the week?
Hours (a) Gross Pay ()
Mathematics
1 answer:
nevsk [136]3 years ago
4 0
A)Total hours she worked =8+7.5+6.5+3+9= 34 hours
b)Amount she was paid= 34 hours x $20.25= 688.50
She was paid $688.50
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Mamont248 [21]
Hey there!

To start, first set up a proportion where x is the cost to make 27 copies:
27/x=150/4.50

Now, solve for x by cross multiplying which should look like this:
27*4.50=x*150

Now simplify and solve for x:
121.5=150x
x=0.81

Therefore, it costs $0.81 to make 27 copies.

Hope this helps!
4 0
3 years ago
Evaluate the function requested. Write your answer as a fraction in lowest terms.<br> Find tan A.
jasenka [17]

For the given triangle, the tan of angle A equals C. \frac{5}{12}.

Step-by-step explanation:

Step 1; In the given triangle, the opposite side has a length of 15 units, the adjacent side has a length of 36 units while the hypotenuse of the triangle measures 39 units. To calculate the tan of angle A we divide the opposite side's length by the adjacent side's length.

cos A = \frac{oppositeside}{adjacentside}.

Step 2; The opposite side's length = 15 units,

The adjacent side's length = 36 units.

cos A = \frac{15}{36}, dividing the numerator and the denominator by 3, we get

cos A = \frac{5}{12}, which is option C.

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3 years ago
To plant a lawn, kristin needs 4 pounds of grass seed peer 1,000 square feet. A diagram of her lawn is shown below. Kristin want
jarptica [38.1K]
She needs 18 pounds for her lawn
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3 years ago
Select the point that is a solution to the system of inequalities
Zarrin [17]
<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

<h2>Why?</h2>

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

y\leq 2x-2

y\leq x^{2} -3x

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2

Substituting into the second inequality, we have:

y\leq x^{2} -3x

1\leq (2)^{2} -3(2)

1\leq (2)^{2} -3(2)

1\leq 4 -6

1\leq -2

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

-1\leq (-2)^{2} -3(-2)

-1\leq 4 +6

-1\leq 10

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

2\leq (4)^{2} -3(4)

2\leq 16 -12

2\leq 4

Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0

Substituting into the second inequality, we have:

y\leq x^{2} -3x

3\leq (1)^{2} -3(1)

3\leq 1 -3

3\leq -2

Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.

Hence, the point that is a solution to the system of inequalities is C(4,2).

Have a nice day!

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3 years ago
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