Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
Step-by-step explanation:
Area of the rectangle = 33 inches sq
Area of a rectangle (formula) = l*b
let the width be x
length = 2 inches + 3x = 2+3x
Area of the rectangle = l*b = 2+3x + x
33 inches sq = 2+3x + x
33 in sq = 2+4x
33/2 = 4x
16.5/4 = x
x = 4.125
width= <u>4.125 inches</u>
length = 2+3x = 2+3(4.125) = <u>14.375</u>
<u></u>
(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)
Answer:
178.3 mm²
Explanation:
The surface area of the regular pyramid is equal to the sum of the base and lateral areas:()
First covert the feet to meters.
1 meter = 3.3 feet.
Divide the total number of feet by 3.3 to get total number of meters:
198 / 3.3 = 60 meters per second.
Multiply meters per second by 15 seconds:
60 x 15 = 900 meters in 15 seconds.
Answer:
39
Step-by-step explanation:
65/2.5 then x 1.5
