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3 years ago

5x increased by 120%

Mathematics

1 answer:

Vlad [161]3 years ago

3 0

"Increased by" means to multiply.

First, change the percentage to a number.

% ⇒ # : %/100

120(%) (120 ÷ 100) = 1.2

Now, you multiply.

5x × 1.2 = 6x

So, your answer is 6x.

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Mars2501 [29]

Answer:

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3 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

4 0

3 years ago

PLS HELP ME I ONLY HAVE 5 MINUTES PLS

Viefleur [7K]

Answer: 71 ft

i hope its the right answeer, do well

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3 years ago

a strawberry cake is cut into three pieces. The Arc measures of all three pieces are congruent. What is the measure of angle XYZ

masya89 [10]

Answer:

I think the strawberry cake measure have to be 360⁰. so the arc measure is 360⁰÷3=100

so we have all three arcs congruent b/c all measures 100⁰

I think XYZ=100⁰

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3 years ago

Read 2 more answers

Select the quadratic equation that has roots x=8 and x=-5

stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

$(x - 8)(x - 5) =0 \\ \\ \therefore {x}^{2} + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\ \\ \therefore {x}^{2} + ( - 13) x+ 40= 0 \\ \\ \huge \red{ \boxed{ \therefore {x}^{2} - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.$

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3 years ago