Which measurement is more precise: 12.3 meters or 16.52 meters ?

A right circular cone has a volume of 24 cubic

VMariaS [17]

Answer:height 2 volume 24 will be r=3.39in

Step-by-step explanation:

7 0

3 years ago

The area of the square, the

const2013 [10]

Answer:

B.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

Please have a look at the attached photo.

My answer:

As given in the question, we know that:

The ratio of the area of the circle to the area of the square is π/4

The formula to find the volume of the cone is:

V = 1/3*the height*the base area

<=> V1 = 1/3*h*π $r^{2}$

The formula to find the volume of the pyramid is:

V2 = 1/3*the height*the base area

<=> V = 1/3*h*4 $r^{2}$

=> the ratio of volume of the cone to the pyramid is:

= $\frac{V1}{V2}$

= (1/3*h*π $r^{2}$ ) / ( 1/3*h*4 $r^{2}$ )

= π/4

S we can conclude that the volume of the cone equals π/4 the volume of the pyramid

Hope it will find you well.

7 0

3 years ago

It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains

sdas [7]

Answer:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

6 0

3 years ago

The length of the AC section is 24 cm. Point B is the interior point of the section AC, AB: CB5: 3. Find the lengths of the segm

shtirl [24]

The lengths of the segments AB and CB are 15 cm and 9 cm respectively

<h3>How to determine the lengths AB and CB?</h3>

The given parameters are:

AC = 24 cm

AB : CB = 5 : 3

This means that:

Length AB = AB/(AB + CB) * AC

So, we have:

Length AB = 5/(5+ 3) * 24

Evaluate

Length AB = 15

The length of CB is calculated using:

CB= AC - AB

So, we have:

CB = 24 - 15

CB = 9

Hence, the lengths of the segments AB and CB are 15 cm and 9 cm respectively

Which measurement is more precise: 12.3 meters or 16.52 meters ? ​

Which measurement is more precise: 12.3 meters or 16.52 meters ?