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3 years ago

1) How many seconds are in three days?

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

7 0

Answer:

259200 seconds

The conversion factor from days to seconds is 86400, which means that 1 day is equal to 86400 seconds:

1 d = 86400 s

To convert 3 days into seconds we have to multiply 3 by the conversion factor in order to get the time amount from days to seconds. We can also form a simple proportion to calculate the result:

1 d → 86400 s

3 d → T(s)

Solve the above proportion to obtain the time T in seconds:

T(s) = 3 d × 86400 s

T(s) = 259200 s

The final result is:

3 d → 259200 s

We conclude that 3 days is equivalent to 259200 seconds:

3 days = 259200 seconds

<em><u>Hope this helps :)</u></em>

morpeh [17]3 years ago

3 0

Answer:

Answer

Step-by-step explanation:

259200

days-->hours-->min-->seconds

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a) The expected value is given by:

$E(X) = np = 50*0.4 = 20$

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c) 1) Random sample (assumed)

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Step-by-step explanation:

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Part a

The expected value is given by:

$E(X) = np = 50*0.4 = 20$

and the variance is given by:

$Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12$

Part b

For this case we want to find this probability:

$P(X>25)= 1-P(X\leq 25)$

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

$P(X>25)= 1-P(X\leq 25)=0.0573$

Part c

1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

$X \sim N(\mu = 20 , \sigma= 3.464)$

Part d

We want this probability:

$P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z$

Part e

For this case we use the continuity correction and we have this:

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)$

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z$

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