Answer:
Equation of line is:
Step-by-step explanation:
Let equation of line be y=mx+c
where m is the slope of line and c is the y-intercept
Line passes through (2, -1/2) and has a slope of 3
i.e. (x,y)=(2, -1/2) and m=3
i.e.
So, equation of line is:
Answer: b= - -log10(7)+3/2
Step-by-step explanation: log 10 (7) -2b-9=-6 : b= - -log10(7)+3/2 (Decimal : b = -1.07745...)
so these are the steps how I got it I did log 10 (7)-2b-9=-6 subtract log 10 (7) -9 from both sides log 10 (7)-2b-9-(log10(7)-9)=-6-(log 10 (7) -9)
Simplify -2b= -log10(7)+3
Divide both sides by -2 -2b/2= - log 10(7)/-2+ 3/-2 if you simplify it should give you b= - -log10(7)+3/2 that should be your answer but i'm not sure those I think that's how you do it let me know if you got it right bye!
1 answer · Mathematics
Best Answer
"Bearing" is the relative position of an object outside the plane compared to the position of the plane.
Heading the the direction the nose of the plane is pointing
Course is the direction that pilot wants the plane to go.
And I am not sure what you call the wind direction other than direction. Wind direction is always the direction the wind is blowing from.
An airplane is traveling at a speed of 240 miles/hour with a HEADING of 110°
If the plane is heading 110 and the wind is blowing from 325
325 - 110 = 215.
215-180 = 35.
you have a "quartering tail wind." Ground speed will be in excess of the airspeed. True course will be south if the indicated heading.
Tailwind component = 56 cos (35) = 46
cross wind component = 56 sin (35) = 32
course deviation = tan^-1(32) / (286) = 6 degrees
116 degrees at 286 kts
this is actually a slight bit of shorthand.
slightly more precise is C^2 = 286^2 + 32^2
C = 288
and you could have used the law of cosines.
You are 16 or 16 and a half about to be 17
