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sukhopar [10]
3 years ago
13

Help me out guys please

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0
The answer is A and B
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The approximate mass of Mars is 6.42 X 10^23 kg write this mass and standard notation
Sauron [17]

Answer:

642,000,000,000,000,000,000,000 kg

Step-by-step explanation: Basically you are multiplying 6.42 by 100,000,000,000,000,000,000,000. That looks really intimidating but it is very simple. All you have to do is move the decimal 23 hops to the right. Moving it to the right makes the number big, were moving it to the left makes the number smaller. We want a bigger number because we are writing the number in standard notation. Right now it is in scientific notation form (scientific notation is used because it is easier and quicker to write than writing 21 zeros).

8 0
3 years ago
Read 2 more answers
sweaters that are regularly sell for 36 dollars and on sale for 30 percent off how much is the discount
Liula [17]

Answer:

Step-by-step explanation: 36-30%= 25.2

your answer should be 25.2

7 0
2 years ago
(m+n)¹⁰; The 6th term will contain m?n?​
Nataly_w [17]

Answer:

252.m^5.n^5

Step-by-step explanation:

6 0
2 years ago
First 100 terms of the following sequence 3 ,7 ,11
Sveta_85 [38]
Given that a_1 = 3, d = 4

<u>Find the nth term:
</u>
a_n = 3 + 4(n - 1)

a_n = 3 + 4n - 4

a_n =  4n - 1

<u>Find the 100th term:</u>

a_{100} = 4(100) - 1 = 399

<u>Find the Sum:</u>

\text{Sum} = 100(\dfrac{a_1 + a_{100}}{2} )= 100 (\dfrac{3 + 399}{2}) = 20100

7 0
3 years ago
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Solve the eqauation 76a^3+19a^2+16a=-4
Crazy boy [7]

Answer:

The solutions are a₁ = -4/19 i, a₂ = 4/19 i and a₃ = -1/4

Step-by-step explanation:

Given the equation 76a³+19a²+16a=-4, for us to solve the equation, we need to find all the factors of the polynomial function. Since the highest degree of the polynomial is 3, the polynomial will have 3 roots.

The equation can also be written as (76a³+19a²)+(16a+4) = 0

On factorizing out the common terms from each parenthesis, we will have;

19a²(4a+1)+4(4a+1) = 0

(19a²+4)(4a+1) = 0

19a²+4 = 0 and 4a+1 = 0

From the first equation;

19a²+4 = 0

19a² = -4

a² = -4/19

a = ±√-4/19

a₁ = -4/19 i, a₂ = 4/19 i (√-1 = i)

From the second equation 4a+1 = 0

4a = -1

a₃ = -1/4

6 0
3 years ago
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