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GaryK [48]
2 years ago
11

The scale on your

Mathematics
1 answer:
motikmotik2 years ago
3 0
(Unless my math is wrong) it is 390 miles
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End of semester help
aliya0001 [1]

Answer:

Step-by-step explanation:

A= 1/2 bh

10.98  = 1/2b (3.6)

10.98=b/2 (3.6)

10.98=b (1.8)

10.98/1.8=b

6.1=b

6 0
2 years ago
What are the slope and y-intercept of the graph? Use the drop-down menus to show your answer.
mina [271]

Answer:

Slope:  Be inclined from a horizontal or vertical line; slant up or down. Slope formula is m=rise/run

Y-Intercept: The vertical axis represents a variable y, a y-intercept or vertical intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system.

5 0
3 years ago
Find r if (r, 6) and (5, -4) are two points on a line with a slope of 5/7 (Hint: use the slope formula)
andreyandreev [35.5K]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have

(r,\ 6),\ (5,\ -4)\\\\m=\dfrac{5}{7}

Substitute

\dfrac{-4-6}{5-r}=\dfrac{5}{7}\\\\\dfrac{-10}{5-r}=\dfrac{5}{7}\qquad|\text{cross multiply}\\\\5(5-r)=(-10)(7)\qquad|\text{use distributive property}\\\\25-5r=-70\qquad|-25\\\\-5r=-95\qquad|:(-5)\\\\\boxed{r=19}

4 0
3 years ago
For every 5 chocolate cones sold, 7 vanilla cones are sold. On Monday, 70 chocolate cones were sold. How many cones were sold IN
FromTheMoon [43]

Answer: 168

Step-by-step explanation: 70/5=14. 14x7=98.  70+98=168.

5 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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