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topjm [15]
3 years ago
14

It’s about right triangles but it’s confusing

Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

Its D

Step-by-step explanation:

Imagine that we have a 2 cm straw that will be the height.

5 cm is for the base

So the upper one must longer than the base

So its 7 cm

Lynna [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Use Pythagorean Theorem, which is for side lengths of right triangles.

a^2 + b^2 = c^2  (c is the hypotenuse)

Common combination is 3-4-5. Just by looking at the answers, I can see A is 3-4-5 except everything is multiplied by 2.

B is wrong. It would be 5-12-13 if it were a RT.

C is wrong. 3-4-5

D is wrong. 4 + 25 = 49 is not an equation.

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Mandarinka [93]
I think its subtracting 
8 0
3 years ago
Solve 5z(z+2)(z−1)=0.
fredd [130]

Answer:

if you are solving for z it is:

Step-by-step explanation:

z=0,-2,1

5 0
3 years ago
The hypotenuse of a 90-45-45 triangle is 20√2. What is the short leg and the long leg>
stepan [7]

Answer:

Both legs would be 20

Step-by-step explanation:
In the image below, it shows the relationship between the legs and the hypotenuse in every 45 45 90 triangle. If we know that the hypotenuse is 20, then the 2 legs are both 20.

I am slightly confused with the problem since they asked for the "short" leg and the "long" leg. Both legs should be the same length because a 45 45 90 triangle is isosceles, with the two legs being the same length.

6 0
2 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
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