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2 years ago

I just need the answer

Mathematics

1 answer:

kogti [31]2 years ago

3 0

The answer is 6 with a remainder of 1. (6 R.1)

Hope this helps!!

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Equation: A number decreased by 5 is equal to 10 (seperate eqaution) The sum of a number and 12 is the same as twice the number.

kirza4 [7]

Answer:

1. 15

2. 12

Explanation:

1. n-5=10

n=10+5

n=15

2. n+12=2n

12=2n-n

12=n

3 0

2 years ago

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

2 years ago

HELP ME 20 POINTS + BRAINLEST GIVE ME THE CORRECT ANSWER

zavuch27 [327]

Answer:

unit rate:2 y-intercept:6

Step-by-step explanation:

4 0

3 years ago

What is the value of x?

uranmaximum [27]

Answer:

$x=\frac{160-51}{2} =54.5$ °

Step-by-step explanation:

"Theorem 9-13: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs."

Basically no matter what other circle, secant or tangent you get, you just use the formula $Outer\angle=\frac{far.point - near.point}{2}$

If you need the outer angle, just put the other angles in and solve

If you need the far or near point angle, re-arrange the formula to get that value.

6 0

2 years ago

Simplify.<br><br> 1/3(1−1/4)^2

xxMikexx [17]

First step is parentheses so subtract 1/4 from 1

(1-1/4) = (4/4 - 1/4) = (3/4)

After parentheses we perform exponent operations

(3/4)^2 = (3^2/4^2) = (9/16)

Finally, after exponent operations we perform multiplications

(1/3)*(9/16) = (3/16)

4 0

2 years ago