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lina2011 [118]
4 years ago
12

What is the volume of a tank that can hold 18 754 Kg of methanol whose density is 0.788g/cm3

Mathematics
1 answer:
Alenkasestr [34]4 years ago
6 0
Density = Mass / Volume
(0.788) = (18.754) / V
0.788V = 18.754
V = (18.754) / (0.788)
V = 23.799
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Solution -9-8(1+4h)= -17
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Step 1. <span>Add </span>9<span> to both sides

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Step 2. Simplify -17+9 to -8

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Step 3. Divide both sides by -8

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Step 4. Cancel 1 on both sides

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 Step 5. Divide both sides by 4

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Done! :) Hope this helps! :)

To check -9-8(1+4h)=-17 follow these steps below:

Step 1. Let h = 0

-9-8*(1+4*0)=-17

Step 2. Simplify 4 * 0 to 0

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Step 3. Simplify 1 + 0 to 1

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<span>
Step 4. </span><span>Simplify  8 * 1 to 8
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<span>
Step 5. </span><span>Simplify -9 -8 to -17
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</span>-17=-17
<span>
Done! :)
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