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DaniilM [7]
3 years ago
6

A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.

Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}

Simplifying, we get;

A=\frac{64 \times 10}{4 (\tan \ 18)}

A=\frac{640}{4 (0.325)}

A=\frac{640}{1.3}

A=642.3

Rounding off to the nearest whole number, we get;

A=642 \ cm^2

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

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3 years ago
the vertex of this parabola is at (2,-1). when the y-value is 0, the x-value is 5. what is the coefficient of the squared term i
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We know that

case a)
the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.

Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1

Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
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1/9 = a
y=(1/9)(x-2)²-1

the answer is
a=1/9


case b)
the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h, 
where (h, k) is the vertex.

Using our vertex, we have:
x=a(y+1)²+2, 
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so
we can use these coordinates to find the value of a:
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the answer is
a=3

see the attached figure 

3 0
3 years ago
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