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mezya [45]
3 years ago
7

Help me plssssssdsssss

Mathematics
1 answer:
Trava [24]3 years ago
4 0

Answer:

The graph is not a function

Step-by-step explanation:

Since the vertical line will pass through more than one point, the graph passes the vertical line test. Therefore, the relation Is Not a function

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Jamie sees a sale at the Gaming Store where all games are the same price. He buys 3 video games. His sister talks him into also
galina1969 [7]

Answer: 3x + 5 = 57.50

Step-by-step explanation:

Assume that the price of one video game is x. Jamie bought 3 video games so the expression will be:

= 3x

His sister talked him into buying two $1.50 candy bars and a $2.00 drink. The total of this is:

= 1.50 + 1.50 + 2.00

= $5.00

The total amount spent on both the video game and the snacks is $57.50. Equation will therefore be:

3x + 5 = 57.50

5 0
2 years ago
What is the simplest form
Soloha48 [4]
√50 + √242 - √2
= √5·5·2 + √11·11·2 -√2
= 5√2 + 11√2 - √2
=  16√2 - √2
= 15√2
6 0
3 years ago
Your car gets about 20 miles per gallon. You are planning to drive to
igor_vitrenko [27]

Answer:

42.5 or 43

Step-by-step explanation:

Since you need to travel 850 miles, and you can travel 20 miles per gallon, you should divide 850 by 20 to get the number of gas cans needed. In doing so, you get 42.5 gas cans, but since it may be asking for whole cans rather than part of a gas can, you might want to write 43 instead. If you were to round down to 42, you would not have enough gas to finish the trip, so you should round up to 43. So, it is up to you if you want to write 42.5 or 43.

Hope this helped somewhat! ;(

5 0
2 years ago
What is “x” increased by 5?
Artyom0805 [142]

Answer:

X+5

Step-by-step explanation:

Hell there!

You just need to express X raised by five in algebraic notation.

:)

7 0
3 years ago
Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
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