Answer:
Wil low
Tun nel
Bri lli ant
Di ffi cult
Exa gge rate
Fit ter
Plan ner
Step-by-step explanation:
I gave you seven just in case.
C (third graph, the parabola); To find if it is a function or not draw a vertical line on the graph. If the vertical line could never intercept the figure more than once anywhere on the graph then it is a function.
The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
<h3>what is measure centre and measure of variation? </h3>
A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.
The measure of central tendency includes the mean, median and mode.
The measure of variation describes the amount of variability or spread in a set of data.
The common measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.
Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
learn more on measure of centre and variation here: brainly.com/question/23769503
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Get the total amount of the 5 tiles and divide it by 5.
Answer:
c) -x^3 + x^2 - 1
Step-by-step explanation:
Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2
(u/v)(x) = u(x)/v(x)
Now plug in the given functions in the above formula, we get
= (x^5 - x^4 + x^2) / -x^2
We can factorize the numerator.
In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.
= x^2 (x^3 - x^2 + 1) / - x^2
Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.
(u/v)(x) = (x^3 - x^2 + 1) / -1
When we dividing the numerator by -1, we get
(u/v)(x) = -x^3 + x^2 - 1
Answer: c) -x^3 + x^2 - 1
Hope you will understand the concept.
Thank you.
