6, if I get it wrong them I'm sorry
Answer:
B = 0
Step-by-step explanation:
do the y2-y1 over x2-x1 to check
so 5-0 = 5
-2-3 = -5
-5/5 = -1 slope
points (-2, 5) and (3, 0)
Answer:
4 / 10
Step-by-step explanation:
Answer:
(x - 3)^2 + (y - 5)^2 = (√89)^2
Step-by-step explanation:
Well if you estimate, you can see that the circle touches one point at (-5, 0) and the center is at about (3, 5).
The standard equation for the circle is (x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center.
So, you can start by plugging in the center. (x - 3)^2 + (y - 5)^2 = r^2
Now, all you have to do is find the radius.
You can do this by connecting the point (-5, 0) to the center.
You will have to use the distance formula:
√(-5 - 3)^2 + (0 - 5)^2 = √64 + 25 = √89
The final equation will be (x - 3)^2 + (y - 5)^2 = (√89)^2
This is the general idea, but my answer may not be correct, so check my steps.
The slope of the given line is
.. (1 -(-3))/(4 -(-4)) = 4/8 = 1/2
Then the perpendicular line will have slope
.. m = -1/(1/2) = -2
The point-slope form of your line is
.. y -3 = -2(x +4) . . . . . . . . . . if you prefer y -y0 = m(x -x0)
.. y = -2(x +4) +3 . . . . . . . . . . if you prefer y = m(x -x0) +y0 as I do.
