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malfutka [58]
3 years ago
7

50 POINTS

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer:

19) x=\frac{7}{2}

20) h(x+3)=4x+14

Step-by-step explanation:

19)

We have the function:

t(x)=7-2x

And we want to find x such that t(x)=0.

So, substitute 0 for t(x):

0=7-2x

Solve for x. Subtract 7 from both sides:

-7=-2x

Divide both sides by -2:

\frac{7}{2}=x

Flip:

x=\frac{7}{2}

20)

We have:

h(x)=4x+2

To find h(x+3), substitute (x+3) for x. This yields:

h(x+3)=4(x+3)+2

Multiply:

h(x+3)=4x+12+2

Add:

h(x+3)=4x+14

And we're done!

MatroZZZ [7]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

(x) = 7 - 2x

Let t(x) =0

0 = 7-2x

Subtract 7 from each side

-7 = -2x

Divide by -2

-7/-2 =-2x/-2

7/2 =x

h(x) = 4x + 2

Replace x with x+3

h(x+3) = 4(x+3) + 2

Distribute

            = 4x+12 +2

            =4x+14

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