3√24 + 2√3(√3-2√18) =
3(√(4*6) + 2√3( √3-2√(2*9)) =
3*2√6 + 2√3 ( √3 - (2*3) √2) =
6√6 + 2√3(√3 - 6√2) =
6√6 + 6 - 12√3*√2 =
6√6 + 6 - 12√(6) =
6 - 6√6 = 6(1-√6)
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
Answer:
C
Step-by-step explanation:
This is because using the formula of area for shapes, you get this equation
A=2(wl+hl+hw)=2·(4·6+4·6+4·4)=128
Answer:
24 area
18.80983669 perimeter
Step-by-step explanation:
1 (6*3/2)*2(1*3/2)+(4*3)
2 trust me
