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julia-pushkina [17]
3 years ago
12

How do you figure out a sum of 2 number, like the sum of 24 and 75?

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

the sum of 24 and 75 just means  24 plus 75, so 24+75=99

your answer is 99

aleksklad [387]3 years ago
5 0
What the previous comment said is absolutely correct
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How do you solve this help​
vfiekz [6]

Answer:

arc PST = 254°

Step-by-step explanation:

arc QPT = 180° because it is a diameter

arc PQ = 74°

arc PT = 180° - 74° = 106°

arc PST = 360° - 106° = 254°

5 0
3 years ago
*BEST ANSWER WILL BE MARKED BRAINLIEST*
Gwar [14]
Alright

for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2


so LM=x√2 is right
NM=x

also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1

so that would be tan(45)=1

so you want to check the 1st one, 3rd one and 5th one

NM=x
LM=x√2
tan(45°)=1 are the answers
4 0
3 years ago
Read 2 more answers
Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

2pi/5*x = arcsin(0.5)

2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
Express 59.2475 in words and expanded notation
enyata [817]

Hey, expressing 59.2475 would look like:


Word form: Fifty-nine and two thousand, four hundred seventy-five ten-thousandths.


Expanded Notation Form:

50 + 9 + 0.2 + 0.04 + 0.007 + 0.0005.

6 0
4 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
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