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Crazy boy [7]
2 years ago
8

I want answer to this question

Mathematics
2 answers:
dem82 [27]2 years ago
6 0

Answer:

a=1 D

Step-by-step explanation:

insert x=1 in the equation

Mashcka [7]2 years ago
3 0

Answer:

When it is divided by x-1 and it has no remainder , then it means substituting x=1 into the polynomial is zero .Because x-1 is a factor.

2 {x}^{3}  - a {x}^{2}  - 7x + 6 \\ x = 1 \\ 2 {(1)}^{3}  - a {(1)}^{2}  - 7(1) + 6 = 0 \\ 2 - a - 7  + 6 = 0 \\ 1 - a = 0 \\ a = 1

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den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

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3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

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