Answer:
5.
4 + 2(-7 - (5 - 15))
= 4 + 2(-7 - (-10))
= 4 + 2(-7 + 10)
= 4 + 2(3)
= 4 + 6
= 10
6.
((6 - 5)^8 - 1)/(-5(-2) - 4)
= (1^8 - 1)/(10 - 4)
= (1 - 1)/6
= 0/6
= 0
7.
(14² - 8²)/(-3(8 - 3²))
= (196 - 64)/(-3(8 - 9))
= (196 - 64)/(-24 + 27)
= 132/3
= 44
If Clarissa had $18,000 in sales during the month of November, and she earns an 8% commission on the dollar value of her sales, then we first need to find out how much she made on commissions alone for the month of November. We can do that by multiplying the percentage by the amount of money she made off of sales.
To do this, we first must convert the percentage into a decimal. We can do this by either dividing the percent by 100, or (my personal shortcut) just shifting the decimal point over 2 places to the left.
8% = 0.08
Now, we multiply the decimal by the amount she made
0.08 * 18000 = 1440
So Clarissa made $1,440 off of commissions. But that's not what the question is asking. It wants to know what percentage of Clarissa's income for the month of November was from commissions. We can do this by adding her base pay to the amount she made from commissions, and then dividing the amount she got from commissions by the total amount she made for the month of November.
2400 + 1440 = 3840
1440 / 2840 = 0.375
We can convert this decimal back to a fraction by multiplying by 100
0.375 = 37.5%
37.5% of Clarissa's pay for the month of November was from commissions.
Hope that helped =)
Answer:
1/2
Step-by-step explanation:
output devided by input
Answer: discrete.
Step-by-step explanation:
Discrete variable
It is a variable whose value is evaluated by counting.
Example: Number of books published in a month.
Continuous variable
It is a variable whose value is evaluated by measuring ( not countable).
Example: Distance: 1.52 m
Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.
here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years
So, the random variable described is discrete.
Answer:
<em>An </em><em>echo</em>
Step-by-step explanation:
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