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Is there a relation between the age difference between husband/wives and the percent of a country that is literate? Researcher

Xelga [282]

Answer:

$y = \beta_1 x + \beta_o$

With $\beta_1$ representing the slope we have that:

$\hat \beta_1 = -0.0437$

$\hat \beta_o = 7.5$

And we are interest on this case the interpretation about the slope and we can conclude that:

For every unit increase in literacy rate (percent of the population that is literate) the age difference (husband minus wife age) falls by 0.0437 units, on average.

Step-by-step explanation:

For this case we have that the regression model adjusted between age difference (husband minus wife age) representing the y variable and literacy rate (percent of the population that is literate) representing the variable x is given by:

$y= -0.0437 x + 7.5$ where $17 \leq x\leq 100$

And we know that the method used in order to adjust the regression line was least squares.

For this case our dependent variable is y = age difference (husband minus wife age) and the independent variable is x=literacy rate (percent of the population that is literate)

If we compare the regression model adjusted with the linear regression model:

$y = \beta_1 x + \beta_o$

With $\beta_1$ representing the slope we have that:

$\hat \beta_1 = -0.0437$

$\hat \beta_o = 7.5$

And we are interest on this case the interpretation about the slope and we can conclude that:

For every unit increase in literacy rate (percent of the population that is literate) the age difference (husband minus wife age) falls by 0.0437 units, on average.

3 0

3 years ago

What is the best estimate

xxMikexx [17]

Answer:

D. 8.5

Step-by-step explanation:

The full value of √8 is 8.48528137...

Hope this helped!

6 0

2 years ago

How many ML of a 35% acid mixture and a 95% acid mixture should be mixed to get 120 ML of a 40% acid mixture?

Anon25 [30]

<u>ANSWER: </u>

110ML of 35% acid solution must be mixed with 10ML of 95% solution to obtain 120ML of 40% solution.

<u>SOLUTION: </u>

First, set up table. fill in the unknowns with variables x and y. The table is attached below.

From the table shown below, we can easily set up the two equations.

Sum of values of two acids = Value of mixture

0.35x + 0.95y = 48

For convenience, we will multiply the entire equation by 100,

35 x + 95y = 4800 ------ (1)

Now, Sum of amounts of each acid = Amount of mixture

x + y = 120 --------- (2)

Multiply eqn 2 with 35 for easy calculation and derive the equation into one variable.

35 = 35x + 35y = 4200

Subtracting equation (2) from (1), we get

0 + 60y = 600

Thus, 60y = 600

$y = \frac{600}{60} = 10$

Substituting y = 10 in (2),

35x + 35(10) = 4200

35x + 350 = 4200

35x = 4200 - 350

35x = 3850

$x = \frac{3850}{35} = 110$

So, we have x = 110 and y = 10

We can conclude that 110ML of 35% acid solution must be mixed with 10ML of 95% solution to obtain 120 ML of 40% solution.

3 0

3 years ago

300% of what number is 51?

Anarel [89]

Set up an equation:
51=3x
17=x
x=17
300% of 17 is 51

8 0

3 years ago

Which value is equivalent to 4

Bumek [7]

Answer:

Hey!!!!!

It looks like you meant to attach a picture, forgot, or your internet connection went out. Because of whatever the cause, we cannot answer your question!

Could you try reposting it?

Thx!

Sahkfam

8 0

3 years ago