PLEASE HURRRYYY Simplify √x2 (2 means squared)

Y=(x-1)(x+7) what are the x-intercepts?

Juli2301 [7.4K]

X-int.= = 1, -7

What can be found in parentheses in an equation like this one is switched to positive or negative.

5 0

3 years ago

B 45° 71° E 27° A D 11. What is mBAC

ANEK [815]

Answer:THE ANSWER IS B MY GUY

Step-by-step explanation:

3 0

2 years ago

Find (f+g)(x) if f(x)=2/x+1 and g(x)=x-2

Semmy [17]

(f+g)(x) if f(x)=2/x+1 and g(x)=x-2

Add f and g together: (f+g)(x) = (2/x) + 1 + x - 2 = (2/x) + x - 1

4 0

3 years ago

Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,

Bas_tet [7]

Answer:

a) $\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96$

$Median = 25$

b) $Mode = 25, 35$

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) $Midrange = \frac{70+13}{3}=41.5$

d) $Q_1 = \frac{20+21}{2} =20.5$

$Q_3 =\frac{35+35}{2}=35$

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96$

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

$Median = 25$

Part b

The mode is the most repeated value on the dataset on this case would be:

$Mode = 25, 35$

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

$Midrange = \frac{Max+Min}{2}$

And if we replace we got:

$Midrange = \frac{70+13}{3}=41.5$

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

$Q_1 = \frac{20+21}{2} =20.5$

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

$Q_3 =\frac{35+35}{2}=35$

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0

3 years ago

Un deposito de agua tiene forma de prisma rectangular con los lados de la base de 25 y 20 metros. Calcula la altura que pueda co

serious [3.7K]

Answer:

La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.

Step-by-step explanation:

Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus 3 dimensiones: longitud*ancho*altura. El volumen se expresa en unidades cúbicas.

En este caso, se conoce la longitud y el ancho, cuyos valores son 25 y 20 metros. A su vez, se sabe que el depósito de agua debe contener 1000 m³. Entonces, siendo:

Volumen= longitud*ancho*altura

Y reemplazando los valores se obtiene:

1000 m³= 25 m* 20 m* altura

Resolviendo:

1000 m³= 500 m²* altura

$altura=\frac{1000 m^{3} }{500 m^{2} }$

altura= 2 m

La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.

7 0

2 years ago