Match each word problem to the equation that models it. tiles the sum of the squares of two positive integers is 394. if one int
eger is 2 less than the other and the larger integer is x, find the integers.
1 answer:
Let
x--------> the larger integer
y-------> the smaller integer
we know that
x²+y²=394-----> equation 1
x=y+2-----> equation 2
substitute equation 2 in equation 1
[y+2]²+y²=394-----> y²+4y+4+y²=394
2y²+4y-390=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
y=13
x=y+2---> x=13+2---> x=15
the answer isthe numbers are 15 and 13
You might be interested in
Answer:
10
Step-by-step explanation:
Use the slope 9 and then go through (0,0)
Answer:
20%
Step-by-step explanation:
(61200-51000)/51000×100
(102000/51000)×100
0.2×100=20%
Hope that helped! :)
$12 x .20 = $2.40
12 - 2.40 = $9.60
$9.60 x .07 = $0.67
$9.60 + $0.67 = $10.27
Total price (including tax): $10.27
Answer:
Step-by-step explanation:
b.

d.

e.
![\frac{2x^2-10x+12}{x^2-4} *\frac{2+x}{3-x} \\=\frac{2[x^2-5x+6]}{x^2-2^2} *\frac{2+x}{-(-3+x)} \\=\frac{2[x^2-2x-3x+6]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2[x(x-2)-3(x-2)]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2(x-2)(x-3)}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2}{-1} \\=-2](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2-10x%2B12%7D%7Bx%5E2-4%7D%20%2A%5Cfrac%7B2%2Bx%7D%7B3-x%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%5E2-5x%2B6%5D%7D%7Bx%5E2-2%5E2%7D%20%2A%5Cfrac%7B2%2Bx%7D%7B-%28-3%2Bx%29%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%5E2-2x-3x%2B6%5D%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%28x-2%29-3%28x-2%29%5D%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%28x-2%29%28x-3%29%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%7D%7B-1%7D%20%5C%5C%3D-2)
k.
