2x^2-5xy-y^3 if x=-3, and y=-2
2(-3)^2- 5(-3)(-2) -(-2)^3
=2(9) - 5(6) - (-8)
= 18 - 30 + 8
= -4
Answer:
1 & 2 perpudicular
1 & 3 neither
2 & 3 is parallel
Step-by-step explanation:
Answer:
x=4
Step-by-step explanation:
12 * X+3=51
Subtract 3 from each side
12x +3-3 = 51-3
12x = 48
Divide by 12
12x/12 = 48/12
x = 4
The numbers are 15,18
They add to 33 and a difference of 3