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3 years ago

What is the length of the indicated arc?

Mathematics

1 answer:

Ksivusya [100]3 years ago

6 0

Answer:

E. None of the above

Step-by-step explanation:

Arc length = radius • angle in radians

30 deg = 0.523599 rad

L = 12 • 0.523599 = 6.28319

2π = 6.28319

Answer is E. None of the above

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A number is multiplied by 4, and then 6 is added to the product. The result is 18. What is the number? I already know that the a

allsm [11]

You can check your answer by multiplying 3 with 4 <span>and then add 6 to the product. Then your result will be 18.</span>

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3 years ago

7+a+8+a= pls help pls help

Alina [70]

Answer:

15+2a

Step-by-step explanation:

7+a+8+a=15+2a

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2 years ago

1. On a train, it takes 3 days, 5 hours, and 15 minutes to get to from Denver to Seattle by train. How many hours does it take t

jarptica [38.1K]

For
1. its
D=Days
H=Hours
M=Minutes
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But i only have this one right now sorry :P

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2 years ago

0.000000205<br> In standard form

zalisa [80]

Answer:

2.05 × 10⁷

Step-by-step explanation:

0.000000205

We'll move the decimal point after the first non-zero digit (as per the scientific notation rules) and the standard form would be :

=> 2.05 × 10⁷

6 0

2 years ago

Read 2 more answers

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago