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matrenka [14]
3 years ago
15

If int a = 4, int *b = &a , int **c= &b; what is the value store in c.

Computers and Technology
1 answer:
Elenna [48]3 years ago
6 0

Answer:

5.

Explanation:

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Pseudocode is an improvement over the IPO chart because it lays out the a0 sequence of steps for a particular program.
Olegator [25]

Answer:

Yes. Pseudocode is an improvement over the IPO chart because it lays out the sequence of steps for a particular program

Explanation:

The input–process–output (IPO) chart is a widely used approach in systems analysis and software engineering for describing the structure of an information processing program or other process. The chart has three components (Input, Process and Output), and you write the description of each component in plain English, not code or mathematical formulas.

Pseudocode is a procedure for solving a problem in terms of the actions to be executed and the order in which those actions are to be executed.

Pseudocode is an improvement over the IPO chart because it shows the step by step sequence to be followed by a particular program unlike the IPO chart which just break the program into Input, Process and Output.

6 0
3 years ago
What is a command-line interactive scripting environment that provides the commands for almost any management task in a Windows
hoa [83]

Answer:

kqwbxskwsxe

Explanation:

menb dhj

8 0
3 years ago
To view the contents of a file that was compressed with the bzip2 utility, you must used the ____________________ command.
bekas [8.4K]

Answer:

zcat

Explanation:

Zcat is a command line utility for viewing the contents of a compressed file without literally uncompressing it. It expands a compressed file to standard output allowing you to have a look at its contents. In addition, zcat is identical to running gunzip -c command.

8 0
3 years ago
A shuffle of two strings X and Y is formed by interspersing the characters into a new string, keeping the characters of X and Y
levacccp [35]

Shuffle (A[1..m], B[1..n], C[1..m+n]):

Shuf[0, 0] ← True

for j ← 1 to n

Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])

for i ← 1 to n

Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])

for j ← 1 to n

Shuf[i, j] ← False

if A[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]

if B[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]

return Shuf[m, n]

The algorithm runs in O(mn) time.

3 0
3 years ago
what does it mean when my brainly just tells me theres no answers for any of my questions i have the plus and ive been using it
VashaNatasha [74]
Well it might be a glitch or it didn’t save.
3 0
3 years ago
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