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Pavel [41]
3 years ago
14

What is the x-intercept and the y-intercept for x+2y=8

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0
To find the x-intercept, you need to set y equal to zero(think about this on a  graph!)
This will become:
x + 2(0) = 8
If we remove the unnecessary zero:
x = 8
That's the x intercept, which can be expressed as the point (8,0).

To find the y-intercept, you need to set x equal to zero(again, think about that on a graph!)
This becomes:
0 + 2y = 8
Remove the unnecessary 0:
2y = 8
Divide both sides by 2:
y = 4
There ya go! Or, in point form: (0, 4)

Hope this helped! :)
~Chrys
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A 12 ft ladder is leaning against a building. The ladder makes a 45 degree angle with the building how far up is the building do
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Answer:

The ladder reach a height 8.485 ft.

Step-by-step explanation:

The ladder with the building made right angle triangle

The length of the ladder is the hypotenuse 12 ft.

The angle between the ladder and the building is 45°

The height of the ladder reach is the vertical side of the Δ

∴ h = 12 cos 45° = 6√2 = 8.485 ft.

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The number of birdhouses Ben can make varies directly with the amount of time he spends making the birdhouses. He can make 4 bir
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24

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if he can make 4 birdhouses in 1 1/2 hours, 1 1/2 hours x 2 = 3. 8 birdhouses per 3 hours. 3 x 3 = 9 hours, 8 x 3 = 27

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Will 1.11 be more than 1 kilograms?
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Using the method of completing the square, put each circle into the form
tatiyna

Answer:

Standard form: (x-\frac{1}{2})^2 + (y-0)^2 = 15

Center: (\frac{1}{2}, 0)

Radius: r =\sqrt{15}

Step-by-step explanation:

The equation of a circle in the standard form is

(x-h)^{2} + (y-k)^{2} = r^{2}

Where the point (h, k) is the center of the circle

To transform this equation 4x^{2} -4x + 4y^{2} - 59 = 0 this equation  in the standard form we use the method of square.

First, we group similar variables

(4x^{2} -4x) + (4y^{2}) - 59 = 0

Divide both sides of equality by 4

(x^{2} -x) + (y^{2}) - 14.75 = 0

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2=  (-\frac{1}{2})^2 = \frac{1}{4}

Now add (\frac{b}{2})^2 on both sides of the equality

(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})

Factor the expression and simplify the independent terms

(x-\frac{1}{2})^2 + (y^{2}) = 15

(x-\frac{1}{2})^2 + (y-0)^2 = 15

Then

h =\frac{1}{2}\\\\k=0

and the center is (\frac{1}{2}, 0)

radius r =\sqrt{15}

3 0
3 years ago
Help me please! (Look at image.)
Svetradugi [14.3K]
4^2 = 16
so x must be greater than 16
answer
E. 17
F. 19
8 0
2 years ago
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