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Fudgin [204]
3 years ago
9

Help can someone help me on their question just explain it well ♡ so that I understand it ;) ​

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0
Ohh come se diceee uhhh i dont know the answer :)
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If marcus has 13 nickels and dimes in his pocket, and they have a combined value of 100 cents, how many of each coin does he hav
ohaa [14]
He has 13 nickles and 3 dimes
5 0
3 years ago
Using the diagram below, determine what the value of x is. Remember a straight line is 180 degrees and a complete circle is 360
Andreas93 [3]

Answer:

x= -66

Step-by-step explanation:

4 0
3 years ago
Help<br> Simplify. 2−4÷2+2^3
Radda [10]
Hey there!

If we use pemdas:

P - Parentheses
E - Exponents
M - Multiplicatiom
D - Division
A - Addition
S - Subtractiom

We know we have to evaluate the exponent first. Two to the rid power is equal to 8. Therefore, we have:

2 - 4/2 + 8

Next, we do the division. -4/2 = -2, so we have:

2-2 + 8 = 0 + 8 = 8

Hope this helps!
3 0
3 years ago
Read 2 more answers
Pls help! 5,6,7<br> 30 points
Deffense [45]
Jon=x-2 jor=x

2(x-2)=x+6

2x-4=x+6

combine like terms

x=10 Jordan's age

x-2 or 10-2 =8 Jonathan's age

13-10= 3 years apart

when aylon was 3 Karina was 6

2×3 =6

this was 7 years ago(answer)

10-3=7

13-6=7

48-36=12 years apart

when kd was 6 and md 18

3×6=18

30 years ago

36-6=30

48-18=30
3 0
3 years ago
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
2 years ago
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