If you were to graph the linear equation 4x+6y=−12 on the semester test, you would need to determine the x- and y-intercepts, pl
ot them, and connect with a line.
Write the x-intercept of the linear equation 4x+6y=−12 in the first box.
Write the y-intercept of the linear equation 4x+6y=−12 in the second box.
Write the x-intercept of the linear equation 4x+6y=−12 in the first box.
Write the y-intercept of the linear equation 4x+6y=−12 in the second box.
2 answers:
The x intercept is -3, and the y intercept is -2
Step-by-step explanation:
The equation given is 4x+6y= -12
Rewrite the equation in slope intercept form of y=mx +c where c is the y intercept
y=mx+c
6y=-4x-12
y= -4/6 x -12/6
y=-2/3x -2
c= -2
To get x intercept replace value of y in the equation with 0;
y= -2/3 x -2
0= -2/3 x -2
2= -2/3 x
2*3=-2x
6=-2x
6/-2 =x
-3 =x
x intercept is -3
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Linear equations : brainly.com/question/9994201
Keywords : graph, linear equation, intercepts, plot
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Answer:
Step-by-step explanation:
The formula for this is
∠G = 1/2(arcEH - arcHF)
We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF
Filling in the formula with what we have:
which simplifies down a bit to
which simplifies down a bit more to
Multiply both sides by 2 to get rid of the fraction and get:
2(5x - 10) = 178 - 8x which of course simplifies to
10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:
18x = 198 so
x = 11. Now we can find the measure of arcHF:
arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.
arcEH + arcHF = arcEHF so
195 + 105 = arcEHF so
arcEHF = 300°
Answer:
In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.
Step-by-step explanation:
For this case we have that the sample size is n =6
The sample man is defined as :
And we want a normal distribution for the sample mean
In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.
So for this case we need to satisfy the following condition:
Because if we find the parameters we got:
And the deviation would be:
And we satisfy the condition: