Question

The maximum point of the function f (x) = -2x2 + 4x + 6 is: please help me

Answer 1

Step-by-step explanation:

By Completing the Square,

$\begin{align}f(x)&=-2x^2+4x+6\\&=-2(x^2-2x)+6\\&=-2(x^2-2x+1)+8\\&=-2(x-1)^2+8 \end{align}$

Since the first tern is at most zero, the maximum value occurs when

$x=1, f(x)=8$